Phonon frequencies and irreducible representations
Posted: Tue Nov 20, 2018 12:11 pm
Dear All,
I am trying to compute the electron-phonon coupling matrix for an 8 atom cell using ph.x with k-grid of 12x12x6 and q-point 4x4x2.
I am computing each of the 12 q-points separately. For the first q-point (gamma-point), the system has 16 irreps. From the output file one can get all the mode symmetries for each irrep and corresponding frequencies, as shown below:
------------------------------------------------------------------------
Mode symmetry, D_4h(4/mmm) point group:
Atomic displacements:
There are 16 irreducible representations
Representation 1 1 modes -A_1g X_1 M_1 Done
Representation 2 1 modes -A_1g X_1 M_1 Done
Representation 3 1 modes -B_1g X_2 M_2 Done
Representation 4 1 modes -B_1g X_2 M_2 Done
Representation 5 2 modes -E_g X_5 M_5 Done
Representation 6 2 modes -E_g X_5 M_5 Done
Representation 7 2 modes -E_g X_5 M_5 Done
Representation 8 2 modes -E_g X_5 M_5 Done
Representation 9 1 modes -A_2u X_4' M_4' Done
Representation 10 1 modes -A_2u X_4' M_4' Done
Representation 11 1 modes -A_2u X_4' M_4' Done
Representation 12 1 modes -A_2u X_4' M_4' Done
Representation 13 2 modes -E_u X_5' M_5' Done
Representation 14 2 modes -E_u X_5' M_5' Done
Representation 15 2 modes -E_u X_5' M_5' Done
Representation 16 2 modes -E_u X_5' M_5' Done
q = ( 0.000000000 0.000000000 0.000000000 )
**************************************************************************
freq ( 1) = -0.143039 [THz] = -4.771283 [cm-1]
freq ( 2) = 0.141240 [THz] = 4.711264 [cm-1]
freq ( 3) = 0.141240 [THz] = 4.711264 [cm-1]
freq ( 4) = 1.868022 [THz] = 62.310502 [cm-1]
freq ( 5) = 1.868022 [THz] = 62.310502 [cm-1]
freq ( 6) = 2.532549 [THz] = 84.476756 [cm-1]
freq ( 7) = 3.475908 [THz] = 115.943802 [cm-1]
freq ( 8) = 3.475908 [THz] = 115.943802 [cm-1]
freq ( 9) = 4.146052 [THz] = 138.297422 [cm-1]
freq ( 10) = 4.146052 [THz] = 138.297422 [cm-1]
freq ( 11) = 5.200291 [THz] = 173.463047 [cm-1]
freq ( 12) = 5.934808 [THz] = 197.963889 [cm-1]
freq ( 13) = 6.503338 [THz] = 216.928000 [cm-1]
freq ( 14) = 7.792651 [THz] = 259.934858 [cm-1]
freq ( 15) = 8.280964 [THz] = 276.223233 [cm-1]
freq ( 16) = 8.280964 [THz] = 276.223233 [cm-1]
freq ( 17) = 8.684696 [THz] = 289.690268 [cm-1]
freq ( 18) = 8.684696 [THz] = 289.690268 [cm-1]
freq ( 19) = 10.769522 [THz] = 359.232578 [cm-1]
freq ( 20) = 11.594174 [THz] = 386.740014 [cm-1]
freq ( 21) = 11.594174 [THz] = 386.740014 [cm-1]
freq ( 22) = 15.172169 [THz] = 506.089090 [cm-1]
freq ( 23) = 16.389027 [THz] = 546.679088 [cm-1]
freq ( 24) = 16.389027 [THz] = 546.679088 [cm-1]
**************************************************************************
Mode symmetry, D_4h(4/mmm) point group:
freq ( 1 - 1) = -4.8 [cm-1] --> A_2u X_4' M_4' I
freq ( 2 - 3) = 4.7 [cm-1] --> E_u X_5' M_5' I
freq ( 4 - 5) = 62.3 [cm-1] --> E_u X_5' M_5' I
freq ( 6 - 6) = 84.5 [cm-1] --> A_2u X_4' M_4' I
freq ( 7 - 8) = 115.9 [cm-1] --> E_g X_5 M_5 R
freq ( 9 - 10) = 138.3 [cm-1] --> E_g X_5 M_5 R
freq ( 11 - 11) = 173.5 [cm-1] --> A_1g X_1 M_1 R
freq ( 12 - 12) = 198.0 [cm-1] --> A_1g X_1 M_1 R
freq ( 13 - 13) = 216.9 [cm-1] --> B_1g X_2 M_2 R
freq ( 14 - 14) = 259.9 [cm-1] --> A_2u X_4' M_4' I
freq ( 15 - 16) = 276.2 [cm-1] --> E_u X_5' M_5' I
freq ( 17 - 18) = 289.7 [cm-1] --> E_g X_5 M_5 R
freq ( 19 - 19) = 359.2 [cm-1] --> B_1g X_2 M_2 R
freq ( 20 - 21) = 386.7 [cm-1] --> E_u X_5' M_5' I
freq ( 22 - 22) = 506.1 [cm-1] --> A_2u X_4' M_4' I
freq ( 23 - 24) = 546.7 [cm-1] --> E_g X_5 M_5 R
electron-phonon interaction ...
--------------------------------------------------------------------------
By comparing the Raman modes of point groups, I can identify the corresponding frequencies and thereby elph.#iq.#irr.xml File (there are 16 elph.#iq.#irr.xml files).
The next q-point (0.000000000 0.000000000 -0.239442795) also has 16 irreps, but the Raman modes are not specified in this case;
-------------------------------------------------------------------------
Atomic displacements:
There are 16 irreducible representations
Representation 1 2 modes - Done
Representation 2 2 modes - Done
Representation 3 2 modes - Done
Representation 4 1 modes - Done
Representation 5 1 modes - Done
Representation 6 1 modes - Done
Representation 7 2 modes - Done
Representation 8 2 modes - Done
Representation 9 1 modes - Done
Representation 10 1 modes - Done
Representation 11 1 modes - Done
Representation 12 2 modes - Done
Representation 13 1 modes - Done
Representation 14 2 modes - Done
Representation 15 2 modes - Done
Representation 16 1 modes - Done
q = ( 0.000000000 0.000000000 -0.239442795 )
**************************************************************************
freq ( 1) = 1.057811 [THz] = 35.284761 [cm-1]
freq ( 2) = 1.057811 [THz] = 35.284761 [cm-1]
freq ( 3) = 1.480778 [THz] = 49.393431 [cm-1]
freq ( 4) = 1.536907 [THz] = 51.265692 [cm-1]
freq ( 5) = 1.536907 [THz] = 51.265692 [cm-1]
freq ( 6) = 2.357932 [THz] = 78.652135 [cm-1]
freq ( 7) = 3.508436 [THz] = 117.028814 [cm-1]
freq ( 8) = 3.508436 [THz] = 117.028814 [cm-1]
freq ( 9) = 4.136431 [THz] = 137.976482 [cm-1]
freq ( 10) = 4.136431 [THz] = 137.976482 [cm-1]
freq ( 11) = 5.311737 [THz] = 177.180465 [cm-1]
freq ( 12) = 5.687131 [THz] = 189.702287 [cm-1]
freq ( 13) = 6.580806 [THz] = 219.512069 [cm-1]
freq ( 14) = 7.755222 [THz] = 258.686350 [cm-1]
freq ( 15) = 8.278951 [THz] = 276.156083 [cm-1]
freq ( 16) = 8.278951 [THz] = 276.156083 [cm-1]
freq ( 17) = 8.666585 [THz] = 289.086145 [cm-1]
freq ( 18) = 8.666585 [THz] = 289.086145 [cm-1]
freq ( 19) = 10.777740 [THz] = 359.506708 [cm-1]
freq ( 20) = 11.612857 [THz] = 387.363206 [cm-1]
freq ( 21) = 11.612857 [THz] = 387.363206 [cm-1]
freq ( 22) = 15.267973 [THz] = 509.284772 [cm-1]
freq ( 23) = 16.394501 [THz] = 546.861684 [cm-1]
freq ( 24) = 16.394501 [THz] = 546.861684 [cm-1]
**************************************************************************
electron-phonon interaction ...
-------------------------------------------------------------------------
I was using the same version on the same computer. On the latter case, I can't identify the frequencies corresponding to elph.#iq.#irr.xml files. Out of 12 q-points Raman modes are specified only on 5 of them.
Please help me to solve this. Or any other method to get the frequencies corresponding to each irrep.
Thank you for your time and consideration,
Best regards,
Fairoja.
-----------
Fairoja Cheenicode Kabeer
Postdoctoral researcher,
Materials Theory,
Uppsala University,
Uppsala, Sweden.
I am trying to compute the electron-phonon coupling matrix for an 8 atom cell using ph.x with k-grid of 12x12x6 and q-point 4x4x2.
I am computing each of the 12 q-points separately. For the first q-point (gamma-point), the system has 16 irreps. From the output file one can get all the mode symmetries for each irrep and corresponding frequencies, as shown below:
------------------------------------------------------------------------
Mode symmetry, D_4h(4/mmm) point group:
Atomic displacements:
There are 16 irreducible representations
Representation 1 1 modes -A_1g X_1 M_1 Done
Representation 2 1 modes -A_1g X_1 M_1 Done
Representation 3 1 modes -B_1g X_2 M_2 Done
Representation 4 1 modes -B_1g X_2 M_2 Done
Representation 5 2 modes -E_g X_5 M_5 Done
Representation 6 2 modes -E_g X_5 M_5 Done
Representation 7 2 modes -E_g X_5 M_5 Done
Representation 8 2 modes -E_g X_5 M_5 Done
Representation 9 1 modes -A_2u X_4' M_4' Done
Representation 10 1 modes -A_2u X_4' M_4' Done
Representation 11 1 modes -A_2u X_4' M_4' Done
Representation 12 1 modes -A_2u X_4' M_4' Done
Representation 13 2 modes -E_u X_5' M_5' Done
Representation 14 2 modes -E_u X_5' M_5' Done
Representation 15 2 modes -E_u X_5' M_5' Done
Representation 16 2 modes -E_u X_5' M_5' Done
q = ( 0.000000000 0.000000000 0.000000000 )
**************************************************************************
freq ( 1) = -0.143039 [THz] = -4.771283 [cm-1]
freq ( 2) = 0.141240 [THz] = 4.711264 [cm-1]
freq ( 3) = 0.141240 [THz] = 4.711264 [cm-1]
freq ( 4) = 1.868022 [THz] = 62.310502 [cm-1]
freq ( 5) = 1.868022 [THz] = 62.310502 [cm-1]
freq ( 6) = 2.532549 [THz] = 84.476756 [cm-1]
freq ( 7) = 3.475908 [THz] = 115.943802 [cm-1]
freq ( 8) = 3.475908 [THz] = 115.943802 [cm-1]
freq ( 9) = 4.146052 [THz] = 138.297422 [cm-1]
freq ( 10) = 4.146052 [THz] = 138.297422 [cm-1]
freq ( 11) = 5.200291 [THz] = 173.463047 [cm-1]
freq ( 12) = 5.934808 [THz] = 197.963889 [cm-1]
freq ( 13) = 6.503338 [THz] = 216.928000 [cm-1]
freq ( 14) = 7.792651 [THz] = 259.934858 [cm-1]
freq ( 15) = 8.280964 [THz] = 276.223233 [cm-1]
freq ( 16) = 8.280964 [THz] = 276.223233 [cm-1]
freq ( 17) = 8.684696 [THz] = 289.690268 [cm-1]
freq ( 18) = 8.684696 [THz] = 289.690268 [cm-1]
freq ( 19) = 10.769522 [THz] = 359.232578 [cm-1]
freq ( 20) = 11.594174 [THz] = 386.740014 [cm-1]
freq ( 21) = 11.594174 [THz] = 386.740014 [cm-1]
freq ( 22) = 15.172169 [THz] = 506.089090 [cm-1]
freq ( 23) = 16.389027 [THz] = 546.679088 [cm-1]
freq ( 24) = 16.389027 [THz] = 546.679088 [cm-1]
**************************************************************************
Mode symmetry, D_4h(4/mmm) point group:
freq ( 1 - 1) = -4.8 [cm-1] --> A_2u X_4' M_4' I
freq ( 2 - 3) = 4.7 [cm-1] --> E_u X_5' M_5' I
freq ( 4 - 5) = 62.3 [cm-1] --> E_u X_5' M_5' I
freq ( 6 - 6) = 84.5 [cm-1] --> A_2u X_4' M_4' I
freq ( 7 - 8) = 115.9 [cm-1] --> E_g X_5 M_5 R
freq ( 9 - 10) = 138.3 [cm-1] --> E_g X_5 M_5 R
freq ( 11 - 11) = 173.5 [cm-1] --> A_1g X_1 M_1 R
freq ( 12 - 12) = 198.0 [cm-1] --> A_1g X_1 M_1 R
freq ( 13 - 13) = 216.9 [cm-1] --> B_1g X_2 M_2 R
freq ( 14 - 14) = 259.9 [cm-1] --> A_2u X_4' M_4' I
freq ( 15 - 16) = 276.2 [cm-1] --> E_u X_5' M_5' I
freq ( 17 - 18) = 289.7 [cm-1] --> E_g X_5 M_5 R
freq ( 19 - 19) = 359.2 [cm-1] --> B_1g X_2 M_2 R
freq ( 20 - 21) = 386.7 [cm-1] --> E_u X_5' M_5' I
freq ( 22 - 22) = 506.1 [cm-1] --> A_2u X_4' M_4' I
freq ( 23 - 24) = 546.7 [cm-1] --> E_g X_5 M_5 R
electron-phonon interaction ...
--------------------------------------------------------------------------
By comparing the Raman modes of point groups, I can identify the corresponding frequencies and thereby elph.#iq.#irr.xml File (there are 16 elph.#iq.#irr.xml files).
The next q-point (0.000000000 0.000000000 -0.239442795) also has 16 irreps, but the Raman modes are not specified in this case;
-------------------------------------------------------------------------
Atomic displacements:
There are 16 irreducible representations
Representation 1 2 modes - Done
Representation 2 2 modes - Done
Representation 3 2 modes - Done
Representation 4 1 modes - Done
Representation 5 1 modes - Done
Representation 6 1 modes - Done
Representation 7 2 modes - Done
Representation 8 2 modes - Done
Representation 9 1 modes - Done
Representation 10 1 modes - Done
Representation 11 1 modes - Done
Representation 12 2 modes - Done
Representation 13 1 modes - Done
Representation 14 2 modes - Done
Representation 15 2 modes - Done
Representation 16 1 modes - Done
q = ( 0.000000000 0.000000000 -0.239442795 )
**************************************************************************
freq ( 1) = 1.057811 [THz] = 35.284761 [cm-1]
freq ( 2) = 1.057811 [THz] = 35.284761 [cm-1]
freq ( 3) = 1.480778 [THz] = 49.393431 [cm-1]
freq ( 4) = 1.536907 [THz] = 51.265692 [cm-1]
freq ( 5) = 1.536907 [THz] = 51.265692 [cm-1]
freq ( 6) = 2.357932 [THz] = 78.652135 [cm-1]
freq ( 7) = 3.508436 [THz] = 117.028814 [cm-1]
freq ( 8) = 3.508436 [THz] = 117.028814 [cm-1]
freq ( 9) = 4.136431 [THz] = 137.976482 [cm-1]
freq ( 10) = 4.136431 [THz] = 137.976482 [cm-1]
freq ( 11) = 5.311737 [THz] = 177.180465 [cm-1]
freq ( 12) = 5.687131 [THz] = 189.702287 [cm-1]
freq ( 13) = 6.580806 [THz] = 219.512069 [cm-1]
freq ( 14) = 7.755222 [THz] = 258.686350 [cm-1]
freq ( 15) = 8.278951 [THz] = 276.156083 [cm-1]
freq ( 16) = 8.278951 [THz] = 276.156083 [cm-1]
freq ( 17) = 8.666585 [THz] = 289.086145 [cm-1]
freq ( 18) = 8.666585 [THz] = 289.086145 [cm-1]
freq ( 19) = 10.777740 [THz] = 359.506708 [cm-1]
freq ( 20) = 11.612857 [THz] = 387.363206 [cm-1]
freq ( 21) = 11.612857 [THz] = 387.363206 [cm-1]
freq ( 22) = 15.267973 [THz] = 509.284772 [cm-1]
freq ( 23) = 16.394501 [THz] = 546.861684 [cm-1]
freq ( 24) = 16.394501 [THz] = 546.861684 [cm-1]
**************************************************************************
electron-phonon interaction ...
-------------------------------------------------------------------------
I was using the same version on the same computer. On the latter case, I can't identify the frequencies corresponding to elph.#iq.#irr.xml files. Out of 12 q-points Raman modes are specified only on 5 of them.
Please help me to solve this. Or any other method to get the frequencies corresponding to each irrep.
Thank you for your time and consideration,
Best regards,
Fairoja.
-----------
Fairoja Cheenicode Kabeer
Postdoctoral researcher,
Materials Theory,
Uppsala University,
Uppsala, Sweden.