Questions on phonon degeneracy?
Posted: Tue Mar 30, 2021 2:56 am
Dear EPW Developers and Users,
Hi. I have some questions on phonon degeneracy and the EPW output results. Here's my situation.
I calculated an AlAs system with 2 atoms in its unit cell. I followed the process EPW provided to run the code, namely scf, nonscf, phonon and epw. And each step ended successfully without any program error. Then I got ele-ph matrix on coarse mesh by reading file alas.epb1, the file that stores the ele-ph matrix on coarse mesh according to EPW source code. When I checked the EPW results on coarse mesh(4*4*4 k points and 4*4*4 q points in my case), I found there's a dismatch in degeneracy on phonon branch and ele-ph matrix. As you can see in Fig 1, the ele-ph matrix shows a three-fold degeneracy on band m=n=1,k=1(0,0,0) , b=1-6(b for phonon brance), q=2(0,0,-0.25). But the alas.dyn2, the file that stores the phonon information on q=2, shows that the phonon branches should be two-fold degenerate, which can be seen in Fig 2.
Here's my question: the phonon branches only show two-fold degeneracy, why the ele-ph matrix shows three-fold degeneracy ? Do I understand the EPW results correctly? Or is there anything I got wrong? I would appreciate it if you can help me understand this. For your reference, I also uploaded my input files, in case there's anything wrong.
Looking forward to your reply. Thanks a lot.
Yaokun Ye
Ph.D Candidate from Peking University Shenzhen Graduate School.
Fig 1
m n k b q REAL PART IMA PART REAL**2+IMA**2
1 1 1 1 2 0.00779858 -0.03647151 0.00139099
1 1 1 2 2 0.00779858 -0.03647151 0.00139099
1 1 1 3 2 -0.00779858 0.03647151 0.00139099
1 1 1 4 2 0.04084267 0.03582770 0.00295175
1 1 1 5 2 0.04084264 0.03582768 0.00295174
1 1 1 6 2 -0.04084266 -0.03582767 0.00295175
Fig 2
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freq ( 1) = 1.716893 [THz] = 57.269389 [cm-1]
( 0.568443 -0.002332 -0.388001 -0.006058 0.180442 -0.008390 )
( 0.560777 0.023770 -0.382417 -0.023770 0.178360 0.000000 )
freq ( 2) = 1.716893 [THz] = 57.269389 [cm-1]
( -0.119370 0.013434 -0.432241 0.012215 -0.551611 0.025648 )
( -0.118354 0.007776 -0.426890 -0.007776 -0.545245 0.000000 )
freq ( 3) = 4.508202 [THz] = 150.377446 [cm-1]
( -0.239043 0.384982 -0.239043 0.384982 0.239043 -0.384982 )
( -0.357743 -0.000000 -0.357743 -0.000000 0.357743 0.000000 )
freq ( 4) = 11.014391 [THz] = 367.400530 [cm-1]
( -0.248547 -0.015087 0.221975 0.016323 -0.026572 0.001236 )
( 0.696247 0.074849 -0.621440 -0.074849 0.074807 0.000000 )
freq ( 5) = 11.014391 [THz] = 367.400530 [cm-1]
( 0.112998 -0.007857 0.158969 -0.004788 0.271967 -0.012646 )
( -0.318460 0.007313 -0.447201 -0.007313 -0.765661 0.000000 )
freq ( 6) = 11.807806 [THz] = 393.866005 [cm-1]
( -0.083285 0.134132 -0.083285 0.134132 0.083285 -0.134132 )
( 0.555343 0.000000 0.555343 0.000000 -0.555343 0.000000 )
**************************************************************************
Hi. I have some questions on phonon degeneracy and the EPW output results. Here's my situation.
I calculated an AlAs system with 2 atoms in its unit cell. I followed the process EPW provided to run the code, namely scf, nonscf, phonon and epw. And each step ended successfully without any program error. Then I got ele-ph matrix on coarse mesh by reading file alas.epb1, the file that stores the ele-ph matrix on coarse mesh according to EPW source code. When I checked the EPW results on coarse mesh(4*4*4 k points and 4*4*4 q points in my case), I found there's a dismatch in degeneracy on phonon branch and ele-ph matrix. As you can see in Fig 1, the ele-ph matrix shows a three-fold degeneracy on band m=n=1,k=1(0,0,0) , b=1-6(b for phonon brance), q=2(0,0,-0.25). But the alas.dyn2, the file that stores the phonon information on q=2, shows that the phonon branches should be two-fold degenerate, which can be seen in Fig 2.
Here's my question: the phonon branches only show two-fold degeneracy, why the ele-ph matrix shows three-fold degeneracy ? Do I understand the EPW results correctly? Or is there anything I got wrong? I would appreciate it if you can help me understand this. For your reference, I also uploaded my input files, in case there's anything wrong.
Looking forward to your reply. Thanks a lot.
Yaokun Ye
Ph.D Candidate from Peking University Shenzhen Graduate School.
Fig 1
m n k b q REAL PART IMA PART REAL**2+IMA**2
1 1 1 1 2 0.00779858 -0.03647151 0.00139099
1 1 1 2 2 0.00779858 -0.03647151 0.00139099
1 1 1 3 2 -0.00779858 0.03647151 0.00139099
1 1 1 4 2 0.04084267 0.03582770 0.00295175
1 1 1 5 2 0.04084264 0.03582768 0.00295174
1 1 1 6 2 -0.04084266 -0.03582767 0.00295175
Fig 2
**************************************************************************
freq ( 1) = 1.716893 [THz] = 57.269389 [cm-1]
( 0.568443 -0.002332 -0.388001 -0.006058 0.180442 -0.008390 )
( 0.560777 0.023770 -0.382417 -0.023770 0.178360 0.000000 )
freq ( 2) = 1.716893 [THz] = 57.269389 [cm-1]
( -0.119370 0.013434 -0.432241 0.012215 -0.551611 0.025648 )
( -0.118354 0.007776 -0.426890 -0.007776 -0.545245 0.000000 )
freq ( 3) = 4.508202 [THz] = 150.377446 [cm-1]
( -0.239043 0.384982 -0.239043 0.384982 0.239043 -0.384982 )
( -0.357743 -0.000000 -0.357743 -0.000000 0.357743 0.000000 )
freq ( 4) = 11.014391 [THz] = 367.400530 [cm-1]
( -0.248547 -0.015087 0.221975 0.016323 -0.026572 0.001236 )
( 0.696247 0.074849 -0.621440 -0.074849 0.074807 0.000000 )
freq ( 5) = 11.014391 [THz] = 367.400530 [cm-1]
( 0.112998 -0.007857 0.158969 -0.004788 0.271967 -0.012646 )
( -0.318460 0.007313 -0.447201 -0.007313 -0.765661 0.000000 )
freq ( 6) = 11.807806 [THz] = 393.866005 [cm-1]
( -0.083285 0.134132 -0.083285 0.134132 0.083285 -0.134132 )
( 0.555343 0.000000 0.555343 0.000000 -0.555343 0.000000 )
**************************************************************************