Disentanglement convergence criteria not satisfied
Posted: Sun Oct 09, 2016 5:56 am
Dear All,
I have been trying to use EPW to calculate electron-phonon interactions in single layer MoS2. However, I always got "Disentanglement convergence criteria not satisfied" even if I have changed DIS_NUM_ITER to 1000 by modifying the source code of EPW. The Delta (frac.) term always oscillates between 1e-3 to 1e-5.
Could you please give me any suggestion on achieving convergence of disentanglement in Wannier?
My input file epw.in and part of nscf_epw.in are shown below.
Thanks,
Lei
I have been trying to use EPW to calculate electron-phonon interactions in single layer MoS2. However, I always got "Disentanglement convergence criteria not satisfied" even if I have changed DIS_NUM_ITER to 1000 by modifying the source code of EPW. The Delta (frac.) term always oscillates between 1e-3 to 1e-5.
Could you please give me any suggestion on achieving convergence of disentanglement in Wannier?
My input file epw.in and part of nscf_epw.in are shown below.
Thanks,
Lei
Code: Select all
nscf_epw.in
ibrav= 0, nat= 3, ntyp= 2,nbnd=18,
ecutwfc = 100.0
!occupations='smearing', smearing = 'mv', degauss = 0.002
Code: Select all
--
&inputepw
prefix = 'MoS2'
amass(1) = 95.94
amass(2) = 32.065
outdir = './'
iverbosity = 0
elph = .true.
epbwrite = .true.
epbread = .false.
etf_mem = .false.
epwwrite = .true.
epwread = .false.
lpolar = .true.
nbndsub = 11
nbndskip = 0
wannierize = .true.
num_iter = 500
iprint = 2
!dis_win_max = 180.0
!dis_win_min = -120.0
dis_froz_max= -1.8d0
dis_froz_min = -1.9d0
!proj(1) = 'random'
proj(1) = 'Mo:d'
proj(2) = 'S:p'
elinterp = .true.
phinterp = .true.
tshuffle2 = .true.
tphases = .false.
elecselfen = .true.
phonselfen = .true.
a2f = .false.
parallel_k = .true.
parallel_q = .false.
fsthick = 30.0 ! eV
eptemp = 300 ! K
degaussw = 0.05 ! eV
efermi_read = .true.
fermi_energy= -1.806
dvscf_dir = './save/'
filukk = './MoS2.ukk'
nkf1 = 160
nkf2 = 160
nkf3 = 1
nqf1 = 160
nqf2 = 160
nqf3 = 1
nk1 = 16
nk2 = 16
nk3 = 1
nq1 = 8
nq2 = 8
nq3 = 1
/
10 cartesian
0.000000000 0.000000000 0.0000000 0.0312500
0.000000000 0.144337567 0.0000000 0.1875000
0.000000000 0.288675135 0.0000000 0.1875000
0.000000000 0.433012702 0.0000000 0.1875000
0.000000000 -0.577350269 0.0000000 0.0937500
0.125000000 0.216506351 0.0000000 0.1875000
0.125000000 0.360843918 0.0000000 0.3750000
0.125000000 0.505181486 0.0000000 0.3750000
0.250000000 0.433012702 0.0000000 0.1875000
0.250000000 0.577350269 0.0000000 0.1875000